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Resposta  Mensagem 1 de 50 no assunto 
De: BARILOCHENSE6999  (Mensagem original) Enviado: 14/02/2016 16:55
 
 
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Resposta  Mensagem 21 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 09/01/2021 03:41


Resposta  Mensagem 22 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 18/01/2021 18:19
Golden ratio

Resposta  Mensagem 23 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 18/01/2021 19:04
PPT - Golden Ratio (1:1.6) PowerPoint Presentation, free download - ID:3054626

Resposta  Mensagem 24 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 18/01/2021 19:33
Golden ratio pyramid

Resposta  Mensagem 25 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 04/06/2021 18:39

Jain's Realisation on Bruce Cathie - Giseh Pyramid Angle - the Speed Of Light and the Number 72

In the case of Cathie’s discoveries, we find that the lines of magnetic force that made up the Global Grid are always 30 arc-minutes apart, which being half of 60 means half a degree of arc-minutes. So, from Cathie’s discoveries, I know that every half-degree of arc on the Earth’s surface was a potential UFO trackline, for a total of 720 latitude lines and 720 longitude lines.

Bruce Cathie found that by using units of 30 minutes of arc latitude north-south, and 30 minutes of arc longitude east-west, on his Mercator’s map, a grid pattern was formed into which a great number of UFO reports could be fitted.

So I looked at the same Mercato map and visualized the 720 x 720 little squares. Recognizing that 72 is an anointed Number, being the base angle of the Golden Isosceles Triangle as seen in the Pentagram and having many other references.

Let's calculate what 72x72 is, it is 5,184

which as you know is the Giseh Pyramid Angle of 51.84 in Harmonic Maths.
The very interesting connection to this 51.84 degree pyramid angle is seen when it is converted to minutes and seconds of arc: 51.84 x 60 x 60 = 186,624 seconds = Speed Of Light in miles per seconds (mps), an astounding result: the Giseh Pyramid Angle, the base of Kepler's Triangle, has a direct and precise correspondence to the Speed Of Light. Surely this is a form of God Mathematics!

Jain

ps: To convert miles/second to kilometres/second, just think of the Fibonacci Sequence eg: 55mph = 89 km/hr, where 55 and 89 are successive Fib Nos. Their Ratio is approximately 1:1.618, so to convert 186,624 mph into km/hr multiply that number by 1.618… and you get an approximation to 299,792 km/hr for the Speed Of Light. This makes the important connection to the Imperial (Base 12) and Modern Metric (Base 10) systems of measurement to be related by the ubiquitous Golden Ratio.



https://ne-np.facebook.com/jain108academy/videos/jains-realisation-giseh-pyramid-angle-the-speed-of-light-bruce-cathie/974004909692334/


Resposta  Mensagem 26 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 03/08/2021 23:42
No hay ninguna descripción de la foto disponible.
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"Internal consistency (and sanity) check"

With r = 1 and Real_Pi = 3.144605511

After the conversion from deg to rad as follows:

"Real_Radians" = Theta(deg) * (Real_Pi/180)

ALL sin(Theta_rad)^2 + cos(Theta_rad)^2 = 1  
Ver menos
No hay ninguna descripción de la foto disponible.
The mathematical Golden Spiral or Phi Spiral should mimic nature.

And this is what a Golden Spiral or Phi Spiral really should look like.

These are the formulas used in the calculation of the plotting:

Values for Theta in degrees:
(-2400, -2390, -2380... Zero, 10,20...1430, 1440)

r = Phi ^ (theta / 360)
Sine = SIN(Theta*Real_Pi/180) <== this is the true way
Cosine = COS(Theta*Real_Pi/180)

Corroborated the above values, all the way through with: '=sin^2(theta)+cos^2(theta) = 1

Plot points:
x = r * Cosine(Theta) as calculated above
y = r * Sine(Theta) as as calculated above

Extrapolated in the minus(deg) for Theta, that is, below or beyond zero, so you can see the
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Resposta  Mensagem 27 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 11/08/2021 11:45


Resposta  Mensagem 28 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 24/08/2021 20:32


Resposta  Mensagem 29 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 16/09/2021 23:22
The amount of days in a solar year plus the proportions for the Equatorial circumference of the Earth and the proportions of the Great Pyramid of Giza according to Golden Pi = 4/√φ = 3.144605511029693144: The Great Pyramid of Giza is a geodetic model of Planet Earth. The measurements mentioned below are the ideal measurements. A meter is equal to 100 centimeters 1 Solon cubit = 40 times √φ = 50.88078598056276 centimeters. If 1 Solon cubit is divided into 20 equal units of measure then 20 inches can be derived because 1 Solon cubit is equal to 20 inches. 1 Saylen cubit = 50 times √φ = 63.60098247570345 centimeters. If 1 Saylen cubit is divided into 25 equal units of measure then 25 inches can be derived because 1 Saylen cubit is equal to 25 inches. 1 inch = 2 times √φ = 2.544039299028138 centimeters. 1 foot = 12 inches. 1 foot = 24 times √φ = 30.528471588337656 centimeters. If the shortest edge length of a Kepler right triangle is equal to 1 then the hypotenuse of the Kepelr right triangle is equal to The Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 according to the Pythagorean theorem. The Golden ratio in Trigonometry = (cosine (36 degrees) times 2) = 1.618033988749895. If the shortest edge length of a Kepler right triangle is equal to 1 then second longest edge length of the Kepelr right triangle is the square root of the Golden ratio = √φ = 1.272019649514069 according to the Pythagorean theorem. The width for the square base of the Great Pyramid of Giza is equal to 756 feet. • If the shortest edge length of a Kepler right triangle is equal to 1 foot and then the second edge length of the Kepler right triangle is multiplied 378 equal times the result will be the height of the Great Pyramid of Giza = 378 times √φ = 480.823427516318082 feet according to Golden Pi = 4/√φ = 3.144605511029693144. • If the shortest edge length of a Kepler right triangle is equal to 1 foot and then the hypotenuse of the Kepler right triangle is multiplied 378 equal times the result will be the slant height of the Great Pyramid of Giza = 378 times φ = 611.61684774746031 feet according to Golden Pi = 4/√φ = 3.144605511029693144. • If the shorter edge length of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 1 foot and then the diagonal of the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is multiplied 378 equal times the result will be the edge height of the Great Pyramid of Giza = 378 times = Cosine (18) degrees times 2 = 1.902113032590307 = 718.998726319136046 feet according to Golden Pi = 4/√φ = 3.144605511029693144.Cosine (18) degrees times 2 = 1.902113032590307. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. • If the shortest edge length of a Kepler right triangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the second longest edge length of that Kepler right triangle is equal to 38.832815729997479 centimeters.24 times √φ = 30.528471588337656 centimeters times the square root of the Golden ratio = √φ = 1.272019649514069 = 38.832815729997479 centimeters. 1 foot = 24 times √φ = 30.528471588337656 centimeters times the square root of the Golden ratio = √φ = 1.272019649514069 = 38.832815729997479 centimeters times 378 = the height of the Great Pyramid of Giza of Giza = 14678.804345939047062 centimeters. The height of the Great Pyramid of Giza = 14678.804345939047062 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the height of the Great Pyramid of Giza = 480.823427516318088 feet. 378 times √φ = 1.272019649514069 = 480.823427516318088. • If the shortest edge length of a Kepler right triangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the hypotenuse of that Kepler right triangle is equal to 49.39610465451582 centimeters. 24 times √φ = 30.528471588337656 centimeters times the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 = 49.39610465451582 centimeters. 1 foot = 24 times √φ = 30.528471588337656 centimeters times the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 378 = 49.39610465451582 centimeters times 378 = slant the height of the Great Pyramid of Giza = 18671.727559406979971centimeters. The Slant height of the Great Pyramid = 18671.727559406979971 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the slant height of the Great Pyramid of Giza = 611.61684774746031 feet. 378 times √φ = 1.272019649514069 = 611.61684774746031. • If the shortest edge length of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the length of the diagonal of that Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 58.068603673239965 centimeters. 24 times √φ = 30.528471588337656 centimeters times Cosine (18) degrees times 2 = 1.902113032590307 = 58.068603673239965 centimeters. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. 1 foot = 24 times √φ = 30.528471588337656 centimeters times = Cosine (18) degrees times 2 = 1.902113032590307 = 58.068603673239965 centimeters times 378 = the edge height of the Great Pyramid of Giza of Giza = 21949.932188484706835 centimeters. The edge height of the Great Pyramid = 21949.932188484706835 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the edge height of the Great Pyramid of Giza = 718.998726319136046 feet. 378 times Cosine (18) degrees times 2 = 1.902113032590307 = 718.998726319136046. Cosine (18) degrees times 2 = 1.902113032590307. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. A Kepler right triangle can be created from the construction of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle by using Compass and straight edge and obviously a marker for the drawing surface. The amount of days in a Solar year = 4/√φ times 7920 times 5280/(10 ^ 3 times 360) = 365.277376161209156. The amount of days in a Solar year = 4/√φ = 3.144605511029693144 times 7920 times 5280/(10 ^ 3 times 360) = 365.277376161209156. The equatorial circumference of planet Earth = 10 ^ 3 times 360 times 365.277376161209156 = 131499855.41803529616 feet. The equatorial circumference of planet Earth = 4/√φ = 3.144605511029693144 times 7920 = 24905.275647355169727 statute miles. 131499855.41803529616 feet divided by 86400 = half the perimeter of the socle of the Great Pyramid of Giza = 1521.989067338371483 feet. Half the perimeter of the socle of the Great Pyramid of Giza times 86400 is also equal to the equatorial circumference of planet Earth = 131499855.41803529616 feet. 484 divided by √φ times 2 = the width of the socle of the Great Pyramid of Giza = 760.99453366918572 feet. Half the width of the socle of the Great Pyramid of Giza = 380.49726683459286 feet times √φ = 484 feet. 484/√φ times 2 times 2 times 86400 = 131499855.41803529616 feet. 131499855.41803529616 feet divided by 5280 = The perimeter of the socle of the Great Pyramid of Giza = 484/√φ times 8 = 3043.978134676742966 feet. 484 feet /√φ times 8 = 3043.978134676742966 feet times 12 = 24905.275647355169727 statute miles. 24905.275647355169727 statute miles divided by 7920 statute miles = Golden Pi = 4/√φ = 3.144605511029693144. There are 929.28 meters in the square perimeter of the socle of the Great Pyramid of Giza according to Golden Pi = 4/√φ = 3.144605511029693144. 484/√φ times 8 = 3043.978134676742966 times 12 = 36527.737616120915592 divided by 100 = the exact amount of days in a solar year = 365.277376161209156. The equatorial diameter of our planet Earth = 41817600 feet. 41817600 feet divided 86400 = the height of the Great Pyramid of Giza = 378 times √φ = 480.823427516318082 feet plus the height of the socle of the Great Pyramid of Giza = 3.176572483681918 feet. 10 ^ 3 times 360 times 484/(√φ) times 8 times 12/(100) = 131499855.41803529616 feet. The height of the Great Pyramid if Giza is 378 times √φ = 480.823427516318082 feet. The width of the square base of the Great Pyramid of Giza is 756 feet. The perimeter of the square base of the Great Pyramid of Giza = 3024 feet. 9 factorial = 362880. At 10 degrees latitude the length of a degree is 9 factorial =362880 feet. The amount of inches in the perimeter of the square of the Great Pyramid of Giza = 36288. 36288 times 10 = 362880. The width for the square base of the Great Pyramid of Giza = 756 feet. The perimeter of the square base of the Great Pyramid of Giza = 3024 feet. There are 36288 inches in the perimeter of the square base of the Great Pyramid of Giza. 3024 times 12 = 36288. 756 times 4 times 12 = 36288. (9!)/10 = 36288. The equatorial circumference of planet Earth: https://joedubs.com/four-earthly-elements/equatorial-circumference-of-earth/ Kepler right triangle diagram with squares upon the edges of the Kepler right triangle: https://drive.google.com/file/d/1iBtXYy06yv9UWtGP5mwMXyt80vaysFvR/view?usp=sharing Kepler right triangle construction method: https://drive.google.com/file/d/15DNXB_xNP2f2jCroC0FyNUyBYGhVAA2J/view?usp=sharing PYTHAGOREAN THEOREM: https://en.wikipedia.org/wiki/Pythagorean_theorem Golden ratio: https://en.wikipedia.org/wiki/Golden_ratio The history of the meter: The history of the meter: https://www.factinate.com/editorial/meter-history/ The meter: https://en.wikipedia.org/wiki/Metre The meter is based now on the speed of light: https://www.youtube.com/watch?v=vgqUyFaUDcI

Resposta  Mensagem 30 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 06/05/2022 03:59


Resposta  Mensagem 31 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 08/05/2022 04:50


Resposta  Mensagem 32 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 12/05/2022 01:43
GOLDEN TRIANGLE OF CALVIMONT
 
PUERTA DEL SOL DE TIWANAKU
 
PUERTA DEL SOL DE TIWANAKU
PUERTA DEL SOL DE TIWANAKU
La Puerta del Sol de Tiwanaku según el Número de Oro - YouTube

Resposta  Mensagem 33 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 30/05/2022 23:46
2. Antecedentes – La belleza y el número φ

Resposta  Mensagem 34 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 30/05/2022 23:58
Ο χρήστης Tamás Görbe στο Twitter: "Kepler's triangle is a right triangle constructed using the golden ratio. It almost succeeds in squaring the circle due to the remarkable coincidence π√φ/4 ≈ 0.999

Resposta  Mensagem 35 de 50 no assunto 
De: BARILOCHENSE6999 Enviado: 31/05/2022 00:12
Raelian symbol Kepler triangle | golden ratio youtu.be/ADUkb… | Flickr


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