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General: 11 DE SEPTIEMBRE=DIA 254 GREGORIANO (25/4=DIA DE SAN MARCOS=227 COPTO)
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Réponse  Message 1 de 16 de ce thème 
De: BARILOCHENSE6999  (message original) Envoyé: 13/03/2018 18:13

11 de septiembre

<< Septiembre >>
Do Lu Ma Mi Ju Vi






1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
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23 24 25 26 27 28 29
30
MMXVIII
Todos los días

El 11 de septiembre es el 254.º (ducentésimo quincuagésimo cuarto) día del año en el calendario gregoriano y el 255.º en los años bisiestos. Quedan 111 días para finalizar el año.




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Réponse  Message 2 de 16 de ce thème 
De: BARILOCHENSE6999 Envoyé: 15/04/2018 16:41
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¿PORQUE EL CENTRO ES LA VELOCIDAD DE LA LUZ? HAY UN CLARO NEXO 911
 


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Réponse  Message 3 de 16 de ce thème 
De: BARILOCHENSE6999 Envoyé: 06/06/2018 16:37
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EL MISMO DISEÑO DE ORION
22 DE JULIO DIA DE MARIA LA MAGDALENA Y 25 DE ABRIL/227 COPTO DIA DE SAN JUAN MARCOS/MARTE
 
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99. Ezequiel 22:7: Al padre y a la madre despreciaron en ti; al EXTRANJERO trataron con violencia en medio de ti; al huérfano y a la viuda despojaron en ti.
 
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7. Génesis 49:17 Será Dan SERPIENTE junto al camino, Víbora junto a la senda, Que muerde los talones del caballo, Y hace caer hacia atrás al jinete.
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VENECIA=PLAZA SAN MARCOS
11. Proverbios 25:11 MANZANA de oro con figuras de plata 
Es la palabra dicha como conviene.
 
12. Cantares 2:5 Sustentadme con pasas, confortadme con MANZANAs; 
Porque estoy enferma de amor.
 
13. Cantares 7:8 Yo dije: Subiré a la palmera, 
Asiré sus ramas. 
Deja que tus pechos sean como racimos de vid, 
Y el olor de tu boca como de MANZANAs,
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ALLI ESTA LA CONEXION VENUS / VENECIA CON EL 666
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VENUS= PENTAGONO= VENECIA= NUMERO DE ORO= 1.618033
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Réponse  Message 4 de 16 de ce thème 
De: BARILOCHENSE6999 Envoyé: 26/07/2018 13:18
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De: BARILOCHENSE6999 Envoyé: 31/01/2021 13:54


Réponse  Message 6 de 16 de ce thème 
De: BARILOCHENSE6999 Envoyé: 23/09/2021 00:22
MARIANO F. URRESTI "PRESUNTO HIJO DE JESUS Y MARIA MAGDALENA SERIA JUAN  MARCOS" - DESENMASCARANDO LAS FALSAS DOCTRINAS - Gabitos
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The amount of days in a solar year plus the proportions for the Equatorial circumference of the Earth and the proportions of the Great Pyramid of Giza according to Golden Pi = 4/√φ = 3.144605511029693144: The Great Pyramid of Giza is a geodetic model of Planet Earth. The measurements mentioned below are the ideal measurements. A meter is equal to 100 centimeters 1 Solon cubit = 40 times √φ = 50.88078598056276 centimeters. If 1 Solon cubit is divided into 20 equal units of measure then 20 inches can be derived because 1 Solon cubit is equal to 20 inches. 1 Saylen cubit = 50 times √φ = 63.60098247570345 centimeters. If 1 Saylen cubit is divided into 25 equal units of measure then 25 inches can be derived because 1 Saylen cubit is equal to 25 inches. 1 inch = 2 times √φ = 2.544039299028138 centimeters. 1 foot = 12 inches. 1 foot = 24 times √φ = 30.528471588337656 centimeters. If the shortest edge length of a Kepler right triangle is equal to 1 then the hypotenuse of the Kepelr right triangle is equal to The Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 according to the Pythagorean theorem. The Golden ratio in Trigonometry = (cosine (36 degrees) times 2) = 1.618033988749895. If the shortest edge length of a Kepler right triangle is equal to 1 then second longest edge length of the Kepelr right triangle is the square root of the Golden ratio = √φ = 1.272019649514069 according to the Pythagorean theorem. The width for the square base of the Great Pyramid of Giza is equal to 756 feet. • If the shortest edge length of a Kepler right triangle is equal to 1 foot and then the second edge length of the Kepler right triangle is multiplied 378 equal times the result will be the height of the Great Pyramid of Giza = 378 times √φ = 480.823427516318082 feet according to Golden Pi = 4/√φ = 3.144605511029693144. • If the shortest edge length of a Kepler right triangle is equal to 1 foot and then the hypotenuse of the Kepler right triangle is multiplied 378 equal times the result will be the slant height of the Great Pyramid of Giza = 378 times φ = 611.61684774746031 feet according to Golden Pi = 4/√φ = 3.144605511029693144. • If the shorter edge length of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 1 foot and then the diagonal of the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is multiplied 378 equal times the result will be the edge height of the Great Pyramid of Giza = 378 times = Cosine (18) degrees times 2 = 1.902113032590307 = 718.998726319136046 feet according to Golden Pi = 4/√φ = 3.144605511029693144.Cosine (18) degrees times 2 = 1.902113032590307. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. • If the shortest edge length of a Kepler right triangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the second longest edge length of that Kepler right triangle is equal to 38.832815729997479 centimeters.24 times √φ = 30.528471588337656 centimeters times the square root of the Golden ratio = √φ = 1.272019649514069 = 38.832815729997479 centimeters. 1 foot = 24 times √φ = 30.528471588337656 centimeters times the square root of the Golden ratio = √φ = 1.272019649514069 = 38.832815729997479 centimeters times 378 = the height of the Great Pyramid of Giza of Giza = 14678.804345939047062 centimeters. The height of the Great Pyramid of Giza = 14678.804345939047062 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the height of the Great Pyramid of Giza = 480.823427516318088 feet. 378 times √φ = 1.272019649514069 = 480.823427516318088. • If the shortest edge length of a Kepler right triangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the hypotenuse of that Kepler right triangle is equal to 49.39610465451582 centimeters. 24 times √φ = 30.528471588337656 centimeters times the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 = 49.39610465451582 centimeters. 1 foot = 24 times √φ = 30.528471588337656 centimeters times the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 378 = 49.39610465451582 centimeters times 378 = slant the height of the Great Pyramid of Giza = 18671.727559406979971centimeters. The Slant height of the Great Pyramid = 18671.727559406979971 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the slant height of the Great Pyramid of Giza = 611.61684774746031 feet. 378 times √φ = 1.272019649514069 = 611.61684774746031. • If the shortest edge length of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the length of the diagonal of that Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 58.068603673239965 centimeters. 24 times √φ = 30.528471588337656 centimeters times Cosine (18) degrees times 2 = 1.902113032590307 = 58.068603673239965 centimeters. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. 1 foot = 24 times √φ = 30.528471588337656 centimeters times = Cosine (18) degrees times 2 = 1.902113032590307 = 58.068603673239965 centimeters times 378 = the edge height of the Great Pyramid of Giza of Giza = 21949.932188484706835 centimeters. The edge height of the Great Pyramid = 21949.932188484706835 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the edge height of the Great Pyramid of Giza = 718.998726319136046 feet. 378 times Cosine (18) degrees times 2 = 1.902113032590307 = 718.998726319136046. Cosine (18) degrees times 2 = 1.902113032590307. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. A Kepler right triangle can be created from the construction of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle by using Compass and straight edge and obviously a marker for the drawing surface. The amount of days in a Solar year = 4/√φ times 7920 times 5280/(10 ^ 3 times 360) = 365.277376161209156. The amount of days in a Solar year = 4/√φ = 3.144605511029693144 times 7920 times 5280/(10 ^ 3 times 360) = 365.277376161209156. The equatorial circumference of planet Earth = 10 ^ 3 times 360 times 365.277376161209156 = 131499855.41803529616 feet. The equatorial circumference of planet Earth = 4/√φ = 3.144605511029693144 times 7920 = 24905.275647355169727 statute miles. 131499855.41803529616 feet divided by 86400 = half the perimeter of the socle of the Great Pyramid of Giza = 1521.989067338371483 feet. Half the perimeter of the socle of the Great Pyramid of Giza times 86400 is also equal to the equatorial circumference of planet Earth = 131499855.41803529616 feet. 484 divided by √φ times 2 = the width of the socle of the Great Pyramid of Giza = 760.99453366918572 feet. Half the width of the socle of the Great Pyramid of Giza = 380.49726683459286 feet times √φ = 484 feet. 484/√φ times 2 times 2 times 86400 = 131499855.41803529616 feet. 131499855.41803529616 feet divided by 5280 = The perimeter of the socle of the Great Pyramid of Giza = 484/√φ times 8 = 3043.978134676742966 feet. 484 feet /√φ times 8 = 3043.978134676742966 feet times 12 = 24905.275647355169727 statute miles. 24905.275647355169727 statute miles divided by 7920 statute miles = Golden Pi = 4/√φ = 3.144605511029693144. There are 929.28 meters in the square perimeter of the socle of the Great Pyramid of Giza according to Golden Pi = 4/√φ = 3.144605511029693144. 484/√φ times 8 = 3043.978134676742966 times 12 = 36527.737616120915592 divided by 100 = the exact amount of days in a solar year = 365.277376161209156. The equatorial diameter of our planet Earth = 41817600 feet. 41817600 feet divided 86400 = the height of the Great Pyramid of Giza = 378 times √φ = 480.823427516318082 feet plus the height of the socle of the Great Pyramid of Giza = 3.176572483681918 feet. 10 ^ 3 times 360 times 484/(√φ) times 8 times 12/(100) = 131499855.41803529616 feet. The height of the Great Pyramid if Giza is 378 times √φ = 480.823427516318082 feet. The width of the square base of the Great Pyramid of Giza is 756 feet. The perimeter of the square base of the Great Pyramid of Giza = 3024 feet. 9 factorial = 362880. At 10 degrees latitude the length of a degree is 9 factorial =362880 feet. The amount of inches in the perimeter of the square of the Great Pyramid of Giza = 36288. 36288 times 10 = 362880. The width for the square base of the Great Pyramid of Giza = 756 feet. The perimeter of the square base of the Great Pyramid of Giza = 3024 feet. There are 36288 inches in the perimeter of the square base of the Great Pyramid of Giza. 3024 times 12 = 36288. 756 times 4 times 12 = 36288. (9!)/10 = 36288. The equatorial circumference of planet Earth: https://joedubs.com/four-earthly-elements/equatorial-circumference-of-earth/ Kepler right triangle diagram with squares upon the edges of the Kepler right triangle: https://drive.google.com/file/d/1iBtXYy06yv9UWtGP5mwMXyt80vaysFvR/view?usp=sharing Kepler right triangle construction method: https://drive.google.com/file/d/15DNXB_xNP2f2jCroC0FyNUyBYGhVAA2J/view?usp=sharing PYTHAGOREAN THEOREM: https://en.wikipedia.org/wiki/Pythagorean_theorem Golden ratio: https://en.wikipedia.org/wiki/Golden_ratio The history of the meter: The history of the meter: https://www.factinate.com/editorial/meter-history/ The meter: https://en.wikipedia.org/wiki/Metre The meter is based now on the speed of light: https://www.youtube.com/watch?v=vgqUyFaUDcI
 
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Réponse  Message 7 de 16 de ce thème 
De: BARILOCHENSE6999 Envoyé: 30/09/2021 00:00
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EL MESÍAS PONDRÁ SUS PIES SOBRE
EL MONTE DE LOS OLIVOS

En el Judaísmo tradicional y en la literatura Rabínica, el monte de los Olivos es llamado la montaña del Mesías (Mashíaj). Después de que el Mesías (Mashíaj) judío Yeshúa/Jesús resucitara, Él dejó la tierra desde el Monte de los Olivos, para volver otra vez al Cielo (Olam Habá) para sentarse a la diestra del Padre. En Hechos 1:9-12 está escrito:

"Y habiendo dicho estas cosas, viéndolo ellos, [Jesús> fue alzado, y le recibió una nube que le ocultó de sus ojos. Y estando ellos con los ojos puestos en el cielo, entre tanto que él se iba, he aquí se pusieron junto a ellos dos varones con vestiduras blancas, los cuales también les dijeron: Varones galileos, ¿por qué estáis mirando al cielo? Este mismo Jesús, que ha sido tomado de vosotros al cielo, así vendrá como le habéis visto ir al cielo. Entonces volvieron a Jerusalén desde el monte que se llama del Olivar [Olivos>, el cual está cerca de Jerusalén, camino de un día de reposo."

Cuando el Mesías (Mashíaj) judío Yeshúa/Jesús vuelva en Su segunda venida como el Mesías Rey (Mashíaj ben David), Él pondrá Sus pies sobre el monte de los Olivos. En Zacarías 14:3-4, 9 está escrito:

"Después saldrá el Señor…y se afirmarán sus pies en aquel día sobre el monte de los Olivos… y el Señor será rey sobre toda la tierra. En aquel día será uno, y uno será su nombre."

Los pies de la persona que se ponen sobre el monte de los Olivos en Zacarías 14:4, es el Señor en Zacarías 14:3. La palabra traducida como SEÑOR en Zacarías 14:3 es la palabra hebrea YHWH. Los pies de YHWH se pondrán sobre el monte de los Olivos. Esto es los pies del Mesías (Mashíaj) judío Yeshúa/Jesús (Hechos 1:9-12).


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De: BARILOCHENSE6999 Envoyé: 27/10/2021 23:52
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De: BARILOCHENSE6999 Envoyé: 31/10/2021 02:25
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De: BARILOCHENSE6999 Envoyé: 07/03/2022 19:07
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De: BARILOCHENSE6999 Envoyé: 30/06/2024 12:50
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De: BARILOCHENSE6999 Envoyé: 31/03/2025 15:39
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72. The Egyptian Royal Cubit, the Inch, the Metre, and 254

Writer: M CampbellM Campbell Mar 27, 2024

Updated: Apr 16, 2024

 

A centimetre is 2.54 inches. At Giza, the number 254 is found as a factor which links various linear dimensions. What does it mean to multiply or divide a linear measure by 254? What does it mean to convert inches to metres, or vice versa?

 

254 is not the only factor that links the key dimensions at Giza, but it is a common theme. The other factors seem to be based in geometry (such as π , √3), and astronomy (such as 223, 235 and 29.53059).

 
 

 

 

As 29.53059 x 4/3 inches are close to 10 000 / 254 inches, as are 365.242199 / 354.36708 x 100 / 2.61803 inches, they can be used almost interchangeably to interpret the dimensions at Giza.

 

10000 / 254 = 39.3700787402

 

29.53059 x 4/3 = 39.37412

 

365.242199 / 354.36708 x 100 / 2.61803 = 39.368871

 

 
 

 
 

 
 

 

 
 

 

The number 254 is linked to both astronomy and geometry. It is linked to pi, to Phi squared, and to the solar and lunar years, as well as being the number of sidereal months in a Metonic period.

 
 

When linear dimensions at Giza are multiplied or divided by 254, it's not necessarily that in one place inches were used and in another metres were used. The metre and the inch can both be said to co-exist at Giza, and even if the metre hadn't appeared in the 18th century it would still appear at Giza. But the use of 254 could in fact be a reference to the ratio between the solar and lunar years combined with Phi squared, or to pi divided by the mean number of lunations in a year.

 

If we think of possible links between the metre, the inch and the Egyptian royal cubit, the number 254 also makes an appearance, since 2.54 cm are an inch. Converting between inches and metres allows us to see ways of thinking about the Egyptian royal cubit, in relation to geometry and astronomy.

 

 
 

 

The links between these three units, inch, metre and cubit, and to astronomy and geometry, may hint at something of the symbolic and religious significance of the cubit in ancient Egyptian cosmology and astronomy. It could also explain some of the enduring appeal of the metre and the inch.

 

Another interesting connection to be made to the number 254 is that, as Howard Crowhurst points out in his book Carnac the Alignments, there are 127 kerb stones around the base of Knowth, in Ireland.

 
127 is a major prime number (...) and as such is a mirror of the fundamental prime number, One. But it is also half of 254 which is the number of lunar orbits in the 19 year Metonic cycle which also counts 235 full moons. The exact relationship between the metre length and the foot is also to be found through this number since 1 inch = 2.54 cm. Also a right angled triangle with a hypotenuse of 254 m and a base of 235 m has a third side measuring 100.0037 x √10 feet. (1)
 

The presence of the number 127 in Ireland seems to suggest a link to the repeated presence of 254 at Giza. The 127 stones at Knowth also suggest we should take the inch - metre connection seriously when analysing ancient sites.

https://www.mercurialpathways.com/post/72-the-egyptian-royal-cubit

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De: BARILOCHENSE6999 Envoyé: 01/04/2025 17:38
Inches to Centimeters in C# with Examples - Dot Net Tutorials

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Everyday maths 2 (Wales): Session 2: 2.2 | OpenLearn - Open University

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De: BARILOCHENSE6999 Envoyé: 02/04/2025 03:48
Alignment of the Giza pyramids with data measured by Sir W. M. F. Petrie [6] (distances in m). Two numbers have been slightly corrected: The long diagonal is 936.16 m rather than 936.19 m, and one angle is 31° 55' 13' rather than 34° 10' 11' (explanation in [5, p. 96; 6, p. 125]). The relative elevations stem from S. Perring (see: [9, part IV, map 1]). Detailed information is provided in the drawings of Maragioglio and Rinaldi [9]. The angles were calculated from the original distances, given in inches (1 inch = 2.54 cm).

Alignment of the Giza pyramids with data measured by Sir W. M. F. Petrie [6] (distances in m). Two numbers have been slightly corrected: The long diagonal is 936.16 m rather than 936.19 m, and one angle is 31° 55' 13' rather than 34° 10' 11' (explanation in [5, p. 96; 6, p. 125]). The relative elevations stem from S. Perring (see: [9, part IV, map 1]). Detailed information is provided in the drawings of Maragioglio and Rinaldi [9]. The angles were calculated from the original distances, given in inches (1 inch = 2.54 cm).

https://www.researchgate.net/figure/Alignment-of-the-Giza-pyramids-with-data-measured-by-Sir-W-M-F-Petrie-6-distances_fig3_359688325

Réponse  Message 16 de 16 de ce thème 
De: BARILOCHENSE6999 Envoyé: 02/04/2025 03:59
Geometry and Modeling Practice - MathBitsNotebook(Geo)


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