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General: ¿LA MANO DE DIOS DE MARADONA DEMUESTRA EL VERDADERO PENTECOSTES EN SOLSTICIO?
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Respuesta  Mensaje 1 de 10 en el tema 
De: BARILOCHENSE6999  (Mensaje original) Enviado: 05/07/2018 14:48

Fases Lunares para el mes de Junio del año 1986

Lunes Martes Miércoles Jueves Viernes Sábado Domingo
 
 
 
 
 
 
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En el calendario lunar se calculan los años según los ciclos de la luna en lugar de los del sol como se hace en el calendario occidental. En dicho calendario lunar, cada mes lunar corresponde a una lunación, que comprende el período entre dos momentos en que la luna se halla exactamente en la misma fase lunar. Cada mes lunar comprende 29.53 días solares.

Aunque cada día del mes lunar correspondería a una fase lunar, las fases de la luna a las que se conoce con un nombre concreto son la Luna Nueva, Cuarto Creciente, Luna Llena y Cuarto Menguante. Estas fases lunares se asocian a diferentes porcentajes de iluminación o ángulos de fase que van del 0% en la luna nueva, 50% en los cuartos y 100% en la luna llena.

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DíaFase lunar Porcentaje iluminado
7 Luna Nueva En la fase lunar de Luna Nueva la visibilidad es del 0%
14 Cuarto Creciente En la fase lunar de Cuarto Creciente la visibilidad es del 50%
22 Luna Llena En la fase lunar de Luna Llena la visibilidad es del 100%
29 Cuarto Menguante En la fase lunar de Cuarto Menguante la visibilidad es del 50%
 
VERDADERO ROSH HASHANAH/PRIMER DIA DEL PRIMER MES HEBREO=24/2
PRIMER DIA DEL SEGUNDO MES HEBREO (LUNA LLENA)=25/3
PRIMER DIA DEL TERCER MES HEBREO =24/4
PRIMER DIA DEL CUARTO MES HEBREO =23/5
PRIMER DIA DEL QUINTO MES HEBREO = 22/6
 
JUSTO EL DIA QUE MARADONA JUGO EL PARTIDO CON INGLATERRA. CONCRETAMENTE "LA MANO DE DIOS" DE MARADONA DEMUESTRA EL VERDADERO PENTECOSTES HEBREO EN EL CONTEXTO A LA LUNA LLENA EN SOLSTICIO DE VERANO/HEMISFERIO NORTE, OSEA EN PLENITUD SOLAR.
 
 
 

22 de Junio de 1986 Argentina elimina a Inglaterra en el mundial ...

www.chatz.com.ar/.../22-de-junio-de-1986-argentina-elimina-a-ingla...En caché
21 Jun 2012 – La mano de Dios es el nombre con el que se conoce el primer gol anotado por el ex futbolista argentino Diego Armando Maradona en el ...
  •  
     

    22 de Junio de 1986: un texto de Eduardo Sacheri-Revista El Gráfico

    4 Jul 2012 – El domingo siguiente era 22 de junio de 1986. Jugaba Argentina. Jugaba un partido del campeonato mundial de México. Jugaba por cuartos ...
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    Un 22 de Junio como hoy pero de 1986 !! Gloria Mundial - Taringa!

    www.taringa.net/.../Un-22-de-Junio-como-hoy-pero-de-1986-_-Glor...En caché
    ... selección nacional argentina contra la británica ese 22 de junio de 1986 era más que una justa deportiva: apenas cuatro años antes Argentina e Inglaterra se ...
     
     
     


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    Respuesta  Mensaje 3 de 10 en el tema 
    De: BARILOCHENSE6999 Enviado: 08/01/2019 19:06
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    GEMATRIA EN INGLES DE SEED=33
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    hebrew calendar in Simple Gematria Equals: 119 ( h8 e5 b2 r 18 e5 w 23 0 c3 a1 l 12 e5 n 14 d4 a1 r 18
    mary magdalene in Simple Gematria Equals: 119 ( m 13 a1 r 18 y 25 0 m 13 a1 g7 d4 a1 l 12 e5 n 14 e5  
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    11 DE SEPTIEMBRE O SEPTIEMBRE 11

    11/9 O 9/11

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    11 Septembre 2001...?

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    Sapientia Aedificavit Sibi Domum. Es decir, "la sabiduría ha edificado aquí su casa". Resulta curioso que la misma frase aparece en el Evangelio de María Magdalena, un texto apócrifo. Se dice que en el interior de esta iglesia y de otras muchas de Venecia está escondido el tesoro de los templarios. Pero no hay ninguna prueba de ello. Para terminar ya con esta entrada me gustaría que nos acercásemos un momento a uno de los edificios más emblemáticos de Venecia: el Palacio Ducal.
     
     
     
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    "¡Oh profundidad de las riquezas de la sabiduría (sophia)
    y de la ciencia (gnwsiV, gnosis) de Dios!
    ¡Cuán incomprensibles son sus juicios, e inescrutables sus caminos!"
    (Romanos, 11: 33).

     

     
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    milky way in Simple Gematria Equals: 119 ( m 13 i9 l 12 k 11 y 25 0 w 23 a1 y 25 )
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    hebrew calendar in Simple Gematria Equals: 119 ( h8 e5 b2 r 18 e5 w 23 0 c3 a1 l 12 e5 n 14 d4 a1 r 18
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    Respuesta  Mensaje 5 de 10 en el tema 
    De: BARILOCHENSE6999 Enviado: 28/10/2019 17:42

    Fibonacci 60 Repeating Pattern

    The last digit of the numbers in the Fibonacci Sequence form a pattern that repeats after every 60th number:

    0, 1, 1, 2, 3, 5, 8, 3, 1, 4, 5, 9, 4, 3, 7, 0, 7, 7, 4, 1, 5, 6, 1, 7, 8, 5, 3, 8, 1, 9, 0, 9, 9, 8, 7, 5, 2, 7, 9, 6, 5, 1, 6, 7, 3, 0, 3, 3, 6, 9, 5, 4, 9, 3, 2, 5, 7, 2, 9, 1

    This pattern can be seen in the following list of the first 72 Fibonacci numbers:

    0 0
    1 1
    2 1
    3 2
    4 3
    5 5
    6 8
    7 13
    8 21
    9 34
    10 55
    11 89
    12 144
    13 233
    14 377
    15 610
    16 987
    17 1,597
    18 2,584
    19 4,181
    20 6,765
    21 10,946
    22 17,711
    23 28,657
    24 46,368
    25 75,025
    26 121,393
    27 196,418
    28 317,811
    29 514,229
    30 832,040
    31 1,346,269
    32 2,178,309
    33 3,524,578
    34 5,702,887
    35 9,227,465
    36 14,930,352
    37 24,157,817
    38 39,088,169
    39 63,245,986
    40 102,334,155
    41 165,580,141
    42 267,914,296
    43 433,494,437
    44 701,408,733
    45 1,134,903,170
    46 1,836,311,903
    47 2,971,215,073
    48 4,807,526,976
    49 7,778,742,049
    50 12,586,269,025
    51 20,365,011,074
    52 32,951,280,099
    53 53,316,291,173
    54 86,267,571,272
    55 139,583,862,445
    56 225,851,433,717
    57 365,435,296,162
    58 591,286,729,879
    59 956,722,026,041
    60 1,548,008,755,920
    61 2,504,730,781,961
    62 4,052,739,537,881
    63 6,557,470,319,842
    64 10,610,209,857,723
    65 17,167,680,177,565
    66 27,777,890,035,288
    67 44,945,570,212,853
    68 72,723,460,248,141
    69 117,669,030,460,994
    70 190,392,490,709,135
    71 308,061,521,170,129
    72 498,454,011,879,264

    Lucien Khan arranged these 60 digits of the pattern in a circle, as shown in illustration below:

    fibonacci-60-digit-repeating-pattern-copyright-lucien-khan

    Here he found other interesting results:

    • The zeros align with the 4 cardinal points on a compass.
    • The fives align with the 8 other points of the 12 points on a clock.
    • Except for the zeros, the number directly opposite each number adds to 10.

    Lucien postulates that ancient knowledge of these relationships contributed to the development of our modern use of 60 minutes in an hour, and presentation of numbers on the face of the clock.

    I found too that any group of four numbers that are 90 degrees from each other (15 away from each other in the circle) sum to 20, except again for the zeros. As an example, use 1, 7, 9 and 3, which appear one to the right of each of the compass points.

    Additionally, every group of five numbers that define the points of the 12 pentagons on the circle also create a pattern. Four of the pentagons have even-numbered last digits of 0, 2, 4, 6, and 8. The remaining eight pentagons have odd-numbered last digits of 1, 3, 5, 7 and 9.
    fibonacci-60-digit-12-pentagon-pattern

    Another interesting pattern yet was observed by Lucien Khan: The 216th number is this sequence is 619220451666590135228675387863297874269396512. The sum of all the digits in that number add up to 216, as well. He notes that it is believed that the secret or hidden name of God contains 216 characters. There are many other fascinating relationships and sacred geometries, which are presented by Lucien Khan in more detail at the links below.

    https://www.goldennumber.net/fibonacci-60-repeating-pattern/

    Respuesta  Mensaje 6 de 10 en el tema 
    De: BARILOCHENSE6999 Enviado: 30/11/2019 16:51
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    Statue of Liberty

    The height of the Statue of Liberty is 111′-1″ from bottom of foot to top of head. The 7 rays on the crown and the 11 points of the base star echo the proportions of the Great Pyramid’s 7:11 height to base proportion. The superb book Talisman by Graham Hancock and Robert Bauval convincingly shows this goddess is actually the Egyptian Isis.

     

    Image courtesy Elcobbola under the Creative Commons Attribution-Share Alike 3.0 Unported license.

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    hace 3 días - Manipularon la historia a través de las fuentes de los textos en su lenguaje inventado llamado Latín, peeeeero no pudieron cambiar el ... Jose Alfonso Hernando ... la famosa batalla de Troya, y HASTA AHÍ NOS VAMOS PARA VER QUE ... “Las matemáticas nos hacen más libres y menos manipulables”.
    hace 3 días - Principal / Valdeande Magico / ¡¡¡ Visitamos TROYES, donde fue la Guerra de Troya !!! ¡¡¡ Visitamos TROYES, donde fue la Guerra de Troya !!!
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    Troyes, Champagne

    troyes champagne

    Troyes is the former capital of Champagne and is a perfect short trip visit from Paris. At just an hour and a half by train it can be a day trip but a couple of days and an overnight stay would be better because there’s so much to see and do in this lovely, vibrant city.

    A town that is shaped like a Champagne cork in Champagne?

    Troyes is an ancient city, once a Roman town with a direct road from Milan and onwards to Boulogne-sur-Mer on the Opal Coast in the north of France – the route for the invasion of Britain. Later the rich and powerful Counts of Champagne built a palace in Troyes and it was a prosperous place that attracted merchants from all over Europe. The counts fortified their town and though at that time Champagne didn’t even exist, the walls took the form of a Champagne cork.

    Following a huge fire in 1524 that destroyed many of the ancient buildings that were constructed from wood, new brick buildings were erected and many of them remain to this day. Indeed the inhabitants of Troyes lived in these buildings pretty much as they had been for hundreds of years right up until the 1950s. It was a decade when the town council went on a bit of a renovation rampage to improve conditions since many of the old buildings had no bathrooms and poor hygiene conditions.

    Fortunately they didn’t destroy too much and visiting Troyes is like stepping back in time. Every street seems to have its quota of half-timbered houses and there are cobbled streets and tiny alleyways that create a mesmerising maze in the centre of the old town of Troyes.  In the little ruelle des Chats (Cats Alley) you’ll see it is so narrow that the houses lean in and touch via a central gutter at the top and cats could cross from houses on both sides of the roads. At the side of the office of the Mutuelle Societe at 111 rue Emile Zola you can enter a gate and at the back you’ll discover a stunning renaissance house looking exactly as it did when it was built. At the Cour du Mortier d’or, the ancient timber frames still bear the workman’s trademarks.

    Everywhere you go here you’ll discover traces of history from hundreds of years ago, quaint, quirky and irresistibly charming…

    Read the rest of this story in our free magazine – click here to go straight to it! 


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    De: BARILOCHENSE6999 Enviado: 26/11/2020 16:59

    Phi, the Golden Ratio and Geometry

    Golden ratios appears in many geometric constructions, including triangles and squares in circles, the pentagon and also in solids such as the dodecahedron.


     
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    Ancient Metrology - Numbers Don't Lie - World Mysteries Blog

    A. Sokolowski There is an underlying order in Cosmos. Our ancestors discovered it in ancient times and expressed it in their writings and monuments. This article is an invitation to all our visitor to explore and expand this subject. Please share facts that should be mentioned here (via comments and/or e-mail) – if you are […]

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    De: BARILOCHENSE6999 Enviado: 08/08/2020 14:06

    3 Phi and Triangles

    3.1 Phi and the Equilateral Triangle

    equilateral+phiChris and Penny at Regina University's Math Central (Canada) show how we can use any circle to construct on it a hexagon and an equilateral triangle. Joining three pairs of points then reveals a line and its golden section point as follows:
    1. On any circle (centre O), construct the 6 equally spaced points A, B, C, D, E and F on its circumference without altering your compasses, so they are the same distance apart as the radius of the circle. ABCDEF forms a regular hexagon.
    2. Choose every other point to make an equilateral triangle ACE.
    3. On two of the sides of that triangle (AE and AC), mark their mid-points P and Q by joining the centre O to two of the unused points of the hexagon (F and B).
    4. The line PQ is then extended to meet the circle at point R.
      Q is the golden section point of the line PR.
    hex and phiQ is a gold point of PR
    The proof of this is left to you because it is a nice exercise either using coordinate geometry and the equation of the circle and the line PQ to find their point of intersection or else using plane geometry to find the lengths PR and QR.

    The diagram on the left has many golden sections and yet contains only equilateral triangles. Can you make your own design based on this principle?

    Chris and Penny's page shows how to continue using your compasses to make a pentagon with QR as one side. 

    •  Equilateral Triangles and the Golden ratio J F Rigby, Mathematical Gazette vol 72 (1988), pages 27-30.
    http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/phi2DGeomTrig.html

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    Golden Ratio | perfect ratio? The golden ratio and tips for your DIY projects Matematicas Ii, Matematicas Faciles, Quiromancia, Fractales Naturales, Suite De Fibonacci, Espiral Aurea, Numero Aureo, Seccion Aurea, Espiral De Fibonacci

    A perfect ratio? The golden ratio and tips for your DIY projects

    The golden ratio can be found throughout nature and in architecture and art throughout history. Learn about it before you start your next DIY project

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    Earth and Moon 666!

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    Sacred Geometry of the Moon - The Lunation Triangle
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    Phi of God Digital Art by Scott Onstott
    Making the volume of a cube equal to the volume of the sphere ...
    The Golden Ratio and 60 degree (equilateral) triangles in a circle ...
     

    We can even find the golden ratio in the relationship between the equilateral triangle and its circumscribed circle.

    Golden Ratio

    https://blog.kareldonk.com/the-cycle-of-life/
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    La Maddalena: Venice’s mysterious masonic church

    Modelled on the Roman Pantheon, the tiny church of Santa Maria della Maddalena, or simply La Maddalena, is a Venetian mystery. Perhaps its most notable feature are the masonic symbols above the door. The all-seeing eye inside an interlocking circle and triangle is one of the symbols of freemasonry and both the church’s architect and patron were freemasons. The mystery is amplified by the fact that the church is almost always closed to visitors – so much so that I’ve never seen the inside.

    The 18th-century neoclassical edifice we see today is the work of Venetian architect Tommaso Temanza who entirely rebuilt an earlier church using a circular plan inspired by the Pantheon in Rome. The Roman Pantheon itself, one of the best preserved buildings of the antiquity, is a special design echoed by the much later symbols of freemasonry. It incorporates a circular wall plan and a rectangular portico while its circular dome has an eye-like opening in the centre of the roof called an oculus.

    La Maddalena’s site, owned by the patrician Balbo (or Baffo) family, had a church as early as the 13th century. There is some evidence of the family’s association with the Knights Templar. In the 18th century, Venice had an influential fraternity of freemasons whose members also included the famous adventurer Giacomo Casanova. The owners of the old religious site who were also affiliated to the freemasonry contracted Temanza, also a member of the fraternity, to build a masonic church in Venice.

    Judging by the symbol of the all-seeing eye above La Maddalena’s entrance and its Latin inscription attributed to Solomon: Sapientia edificavit sibi domum (“Wisdom has built a home for itself”), Temanza was also a dabbler in the same undercurrent of esoteric freemasonry as Mozart. The architect is buried inside the church and his headstone is apparently decorated with a line and set of compasses, the most common symbol of the freemasons whose members would see themselves as ‘builders’.

    It is also no surprise that this peculiar small masonic church is dedicated to Mary Magdalene. Despite being the first witness to Christ’s resurrection, she is more commonly remembered as a reformed prostitute. This mysterious figure, sometimes rejected by the church, was instead beloved by the freemasonry whose members considered her a symbol of wisdom and the struggle against the obscurantism of the church. With her church in Venice almost never open to visitors, this struggle is apparently real.

    https://romanholiday.co.za/la-maddalena-venices-mysterious-masonic-church/

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    The amount of days in a solar year plus the proportions for the Equatorial circumference of the Earth and the proportions of the Great Pyramid of Giza according to Golden Pi = 4/√φ = 3.144605511029693144: The Great Pyramid of Giza is a geodetic model of Planet Earth. The measurements mentioned below are the ideal measurements. A meter is equal to 100 centimeters 1 Solon cubit = 40 times √φ = 50.88078598056276 centimeters. If 1 Solon cubit is divided into 20 equal units of measure then 20 inches can be derived because 1 Solon cubit is equal to 20 inches. 1 Saylen cubit = 50 times √φ = 63.60098247570345 centimeters. If 1 Saylen cubit is divided into 25 equal units of measure then 25 inches can be derived because 1 Saylen cubit is equal to 25 inches. 1 inch = 2 times √φ = 2.544039299028138 centimeters. 1 foot = 12 inches. 1 foot = 24 times √φ = 30.528471588337656 centimeters. If the shortest edge length of a Kepler right triangle is equal to 1 then the hypotenuse of the Kepelr right triangle is equal to The Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 according to the Pythagorean theorem. The Golden ratio in Trigonometry = (cosine (36 degrees) times 2) = 1.618033988749895. If the shortest edge length of a Kepler right triangle is equal to 1 then second longest edge length of the Kepelr right triangle is the square root of the Golden ratio = √φ = 1.272019649514069 according to the Pythagorean theorem. The width for the square base of the Great Pyramid of Giza is equal to 756 feet. • If the shortest edge length of a Kepler right triangle is equal to 1 foot and then the second edge length of the Kepler right triangle is multiplied 378 equal times the result will be the height of the Great Pyramid of Giza = 378 times √φ = 480.823427516318082 feet according to Golden Pi = 4/√φ = 3.144605511029693144. • If the shortest edge length of a Kepler right triangle is equal to 1 foot and then the hypotenuse of the Kepler right triangle is multiplied 378 equal times the result will be the slant height of the Great Pyramid of Giza = 378 times φ = 611.61684774746031 feet according to Golden Pi = 4/√φ = 3.144605511029693144. • If the shorter edge length of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 1 foot and then the diagonal of the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is multiplied 378 equal times the result will be the edge height of the Great Pyramid of Giza = 378 times = Cosine (18) degrees times 2 = 1.902113032590307 = 718.998726319136046 feet according to Golden Pi = 4/√φ = 3.144605511029693144.Cosine (18) degrees times 2 = 1.902113032590307. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. • If the shortest edge length of a Kepler right triangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the second longest edge length of that Kepler right triangle is equal to 38.832815729997479 centimeters.24 times √φ = 30.528471588337656 centimeters times the square root of the Golden ratio = √φ = 1.272019649514069 = 38.832815729997479 centimeters. 1 foot = 24 times √φ = 30.528471588337656 centimeters times the square root of the Golden ratio = √φ = 1.272019649514069 = 38.832815729997479 centimeters times 378 = the height of the Great Pyramid of Giza of Giza = 14678.804345939047062 centimeters. The height of the Great Pyramid of Giza = 14678.804345939047062 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the height of the Great Pyramid of Giza = 480.823427516318088 feet. 378 times √φ = 1.272019649514069 = 480.823427516318088. • If the shortest edge length of a Kepler right triangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the hypotenuse of that Kepler right triangle is equal to 49.39610465451582 centimeters. 24 times √φ = 30.528471588337656 centimeters times the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 = 49.39610465451582 centimeters. 1 foot = 24 times √φ = 30.528471588337656 centimeters times the Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 378 = 49.39610465451582 centimeters times 378 = slant the height of the Great Pyramid of Giza = 18671.727559406979971centimeters. The Slant height of the Great Pyramid = 18671.727559406979971 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the slant height of the Great Pyramid of Giza = 611.61684774746031 feet. 378 times √φ = 1.272019649514069 = 611.61684774746031. • If the shortest edge length of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 1 foot = 24 times √φ = 30.528471588337656 centimeters then the length of the diagonal of that Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle is equal to 58.068603673239965 centimeters. 24 times √φ = 30.528471588337656 centimeters times Cosine (18) degrees times 2 = 1.902113032590307 = 58.068603673239965 centimeters. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. 1 foot = 24 times √φ = 30.528471588337656 centimeters times = Cosine (18) degrees times 2 = 1.902113032590307 = 58.068603673239965 centimeters times 378 = the edge height of the Great Pyramid of Giza of Giza = 21949.932188484706835 centimeters. The edge height of the Great Pyramid = 21949.932188484706835 centimeters divided by 24 times √φ = 30.528471588337656 centimeters = the edge height of the Great Pyramid of Giza = 718.998726319136046 feet. 378 times Cosine (18) degrees times 2 = 1.902113032590307 = 718.998726319136046. Cosine (18) degrees times 2 = 1.902113032590307. Cosine (18) degrees times 2 = 1.902113032590307 squared = φ plus 2 = 3.618033988749895. A Kepler right triangle can be created from the construction of a Golden ratio = (√(5) plus 1)/2 = φ = 1.618033988749895 rectangle by using Compass and straight edge and obviously a marker for the drawing surface. The amount of days in a Solar year = 4/√φ times 7920 times 5280/(10 ^ 3 times 360) = 365.277376161209156. The amount of days in a Solar year = 4/√φ = 3.144605511029693144 times 7920 times 5280/(10 ^ 3 times 360) = 365.277376161209156. The equatorial circumference of planet Earth = 10 ^ 3 times 360 times 365.277376161209156 = 131499855.41803529616 feet. The equatorial circumference of planet Earth = 4/√φ = 3.144605511029693144 times 7920 = 24905.275647355169727 statute miles. 131499855.41803529616 feet divided by 86400 = half the perimeter of the socle of the Great Pyramid of Giza = 1521.989067338371483 feet. Half the perimeter of the socle of the Great Pyramid of Giza times 86400 is also equal to the equatorial circumference of planet Earth = 131499855.41803529616 feet. 484 divided by √φ times 2 = the width of the socle of the Great Pyramid of Giza = 760.99453366918572 feet. Half the width of the socle of the Great Pyramid of Giza = 380.49726683459286 feet times √φ = 484 feet. 484/√φ times 2 times 2 times 86400 = 131499855.41803529616 feet. 131499855.41803529616 feet divided by 5280 = The perimeter of the socle of the Great Pyramid of Giza = 484/√φ times 8 = 3043.978134676742966 feet. 484 feet /√φ times 8 = 3043.978134676742966 feet times 12 = 24905.275647355169727 statute miles. 24905.275647355169727 statute miles divided by 7920 statute miles = Golden Pi = 4/√φ = 3.144605511029693144. There are 929.28 meters in the square perimeter of the socle of the Great Pyramid of Giza according to Golden Pi = 4/√φ = 3.144605511029693144. 484/√φ times 8 = 3043.978134676742966 times 12 = 36527.737616120915592 divided by 100 = the exact amount of days in a solar year = 365.277376161209156. The equatorial diameter of our planet Earth = 41817600 feet. 41817600 feet divided 86400 = the height of the Great Pyramid of Giza = 378 times √φ = 480.823427516318082 feet plus the height of the socle of the Great Pyramid of Giza = 3.176572483681918 feet. 10 ^ 3 times 360 times 484/(√φ) times 8 times 12/(100) = 131499855.41803529616 feet. The height of the Great Pyramid if Giza is 378 times √φ = 480.823427516318082 feet. The width of the square base of the Great Pyramid of Giza is 756 feet. The perimeter of the square base of the Great Pyramid of Giza = 3024 feet. 9 factorial = 362880. At 10 degrees latitude the length of a degree is 9 factorial =362880 feet. The amount of inches in the perimeter of the square of the Great Pyramid of Giza = 36288. 36288 times 10 = 362880. The width for the square base of the Great Pyramid of Giza = 756 feet. The perimeter of the square base of the Great Pyramid of Giza = 3024 feet. There are 36288 inches in the perimeter of the square base of the Great Pyramid of Giza. 3024 times 12 = 36288. 756 times 4 times 12 = 36288. (9!)/10 = 36288. The equatorial circumference of planet Earth: https://joedubs.com/four-earthly-elements/equatorial-circumference-of-earth/ Kepler right triangle diagram with squares upon the edges of the Kepler right triangle: https://drive.google.com/file/d/1iBtXYy06yv9UWtGP5mwMXyt80vaysFvR/view?usp=sharing Kepler right triangle construction method: https://drive.google.com/file/d/15DNXB_xNP2f2jCroC0FyNUyBYGhVAA2J/view?usp=sharing PYTHAGOREAN THEOREM: https://en.wikipedia.org/wiki/Pythagorean_theorem Golden ratio: https://en.wikipedia.org/wiki/Golden_ratio The history of the meter: The history of the meter: https://www.factinate.com/editorial/meter-history/ The meter: https://en.wikipedia.org/wiki/Metre The meter is based now on the speed of light: https://www.youtube.com/watch?v=vgqUyFaUDcI
     
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