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General: LEVITATION SUPERCONDUCTOR MAGNETISM AC (ALTERNATING) CURRENT LEVITATION
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Respuesta  Mensaje 1 de 5 en el tema 
De: BARILOCHENSE6999  (Mensaje original) Enviado: 11/10/2024 04:23

LEVITATION

 

My notes of the excellent lectures 19 and 20 by “Walter Lewin. 8.02 Electricity and Magnetism. Spring 2002. The material is neither affiliated with nor endorsed by MIT, https://youtube.com. License: Creative Commons BY-NC-SA.”

 

Using superconductors

Superconductivity was discovered by Kamerlingh Onnes, a Dutch physicist in 1911. He discovered how to make liquid helium, that he used to cool various substances. He discovered that when you cool mercury to 4�K, that the electrical resistance goes down to zero. He received the Nobel Prize in 1913.

Heike Kamerlingh Onnes (1913)
Les Prix Nobel 1913, p. 52 / Nobel foundation / PD

 

 At higher temperature

We can only understand superconductivity using quantum mechanics, and even quantum mechanics has a major problems explaining all the phenomena about superconductivity. The problem started in 1986, when two scientists in Zurich, Muller and Bednorz, discovered that certain alloys can be made superconducting at a temperature as high as 35�K. Theorist earlier had proven that it was impossible to ever get superconductivity at that temperature. This was such as splash in the community, that they were awarded the Nobel Price within one year (1987).

As of today, theorists still cannot explain fully why there is what’s called high-temperature superconductivity. Today’s record is 135�K. Since liquid nitrogen has a temperature of 77�K, anyone can now play with superconducting materials, because liquid nitrogen is easy to come by.

If you have zero resistance in a material, you can run an extremely high current through it and therefore get magnetic fields as high as 6T. Such superconducting coils are used in the colliders that we talked about earlier.

No electric field can exist in a superconductor. If there were an electric field, there would be a potential difference over the superconductor. Ohm’s law tells you that if the potential difference is not zero, and the resistance is zero, then the current would go to infinity.�=�↑∞�=0

 Levitating magnet

If we approach a superconducting disk with a magnet, there will be a change in magnetic flux. Based on Faraday’s law there will be an EMF generated in the disk.

 

However, that EMF must remain zero because the resistance � of the superconductor is zero. No matter what the current is, there cannot be an EMF�=�↑∞�=0

As the magnet approaches, eddy currents are going to flow inside the superconductor. These eddy currents create a magnetic field themselves. These eddy current make sure that the net change in magnetic flux ���/�� is always zero.�����=0

Since there was no magnetic flux when the magnet was high up, and the eddy current cancel out any change in magnetic flux. there will never be a net magnetic flux inside the superconductor.

 Magnetic pressure

The sketch on the left shows, the magnetic field from the bar magnet and of the eddy currents in the superconductor. The top of the superconductor acts as a north pole, repelling the north pole of the magnet.

Magnetic field of magnet and from induced current 
 
 Net magnetic field

 

The sketch on the right shows, the superposition of the two fields. You get a squeezed field between the magnet and the superconductor. When you have such a squeezed magnetic field, there is magnetic pressure because the north poles repel each other. The magnetic pressure � can be expressed as(magnetic pressure)�=�22�0[Nm2]

The end result is that the magnet is repelled. Pushed up by the superconductor. Even when you start rotating the magnet, the eddy currents will instantaneously adjust to always repel the magnet.

A superconductor levitating a permanent magnet
Julien Bobroff &Frederic Bouquet / CC BY-SA 3.0 / supraconductivite.fr

 

The eddy current never dissipates any heat. There is no �2�, because � is zero. So you never lose the eddy current. The currents never die out! This is different with the next form of levitation.

Using velocity

Another for of levitation is where you move a magnet fast over a conducting surface.

 

As the magnet overs over the conducting plate, the magnetic flux through that plate will change. Lenz’s law says it will run an eddy currents so that its magnetic field opposes that of the magnet.

2BD Fieldlines thicker Magnetic field of magnet and induced field 
 
 2BD Fieldlines thicker 2 Net magnetic field

 

The north pole of the eddy current opposes the north pole of the magnet. If the magnet has an high enough speed, so that the change in magnetic flux ��/�� is high, the train can float. Many of tons of weight can be made to float.

For the train to float, it has to keep going. If the trains stops the eddy current will die out. There’s no longer a ��/��, but there is resistance in the conductor. So you get Ohmic dissipation �2�. The heat will dissipated in the conductor, and the train will just plunge down.

That was not the case with the superconductor, because superconductors don’t dissipate any heat. But the idea is the same, as you get a squeezed magnetic field that causes magnetic pressure.

Transrapid 09 in Norddeutschland.
Állatka / PD / wikipedia.org

Japan and Germany are leaders in the world of magnetic levitation trains. There is an enormous reduction in friction if you can have a train that is not in contact with the rails. Speeds have been recorded up to 550km/h. It is no more expensive as building a 4-lane highway at 30M$/mile.

Using alternating current

There is a third form of magnetic levitation whereby we don’t need any speed or superconductors. We feed alternating current (AC) to a solenoid placed over a conducting plate.

Magnetic field from solenoid

 

Say, at one moment in time the magnetic field is shown below and is increasing. Then of course the magnetic field turns around, up, down, up, down, because it’s AC. We have this continuous magnetic field change, so we have a continuous change in magnetic flux in that plate.

At the moment in time, that the �→-field is down and increasing, we’re going to get an eddy current which will create an opposing magnetic field. Again, you have two opposing north poles. So again, the eddy current in the conducting plate is responsible for a magnetic field and the two repel each other.

Induced magnetic field

 

A little later in time, the magnetic field strength will decrease. When that happens the eddy current will reverse direction, and the two will attract each other. It now seems quite reasonable that half the time they will attract each other and the other half of the time they will repel each other. That however is not the case. There will be a net repelling force, that we will explain that in the next lecture.

Levitating Barbecue! Electromagnetic Induction
Veritasium / Palais de la Découverte, Paris

 

AC Levitation – part 2

(Continuing “Levitation using AC current“”)

 

Induced magnetic field

 

The behavior depends on the AC current’s sine wave

  • Between the 0° and 90° of the current, the magnetic field points down and is increasing in strength. Because it is increasing in strength, the eddy currents will be in the opposite direction. The magnetic fields will repel each other. (As shown in the illustration above.)
  • Between the 90° and 180° of the the current, the magnetic field of the inductor still points down, but is decreasing in strength. Because it is decreasing, ��/�� is negative and the EMF flips over. Now, the eddy currents are in the same direction as the current through the solenoid. The magnetic fields will attract.

 

One would expect that half the time the solenoid and the conductor attract, and half the time they repel. So the net effect would be no levitation. However, it is not that simple ..

 The secret

As we will see in RL Circuit with AC current, the secret lies in the self-inductance. The eddy current runs over a path which has a resistance � and self-inductance �. So in the conductor we get an induced current that is delayed over the induced EMF, driven by equation (???).�=arctan⁡���

The red curve is the current for the coil. When it is positive, it is clockwise, otherwise anti-clockwise. The green curve is the EMV which is induced in the conductor.

 

Notice when the magnetic field increases, the current goes up in the coil, then the EMF in the conductor is in such a direction that it opposes the change in that magnetic field.

Now when the magnetic field decreases, the current in the coil decreases, immediately the EMF flips over. Therefore if the induced current and the induced EMF were in phase with each other, half the time you would have attraction, and half the time you would have that the two repel each other.

When we add a blue curve representing the induced current,

 

If there is no phase shift between the induced EMF and the induced current, half the time the blue and red curve are in opposite direction.

Now, if I have a phase delay, so that the induced current comes later than the EMF, say 90°

 

Now, the red curve and the blue curve are always in opposite directions. Now all the time there is a repelling force.

Even if the phase delay is less than 90°, the net result is that on average you get a repelling force. So the secret of the repelling force, lies in the fact that there is a finite self-inductance in the conductor.

If � is zero, then of course we have a superconductor, then � is always 90°. The floating magnet above a super conductor, was such an ideal case.

https://coertvonk.com/physics/electromagnetism/magnetism/levitation-30367


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De: BARILOCHENSE6999 Enviado: 11/10/2024 04:27
Magnetic Levitation - The Complete Physics of the Fastest Train Ever Built  - Read book online

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De: BARILOCHENSE6999 Enviado: 11/10/2024 04:34

LEVITRON: PLAYING WITH MAGNETIC LEVITATION

 

IMPORTANT ELECTROMAGNETIC PRINCIPLES BEHIND THE LEVITRON

Physics

There are two main properties that allow the Levitron to levitate stably. The first is the magnetic repulsion, which provides the force for levitation. The second are gyroscopic effects due to the spinning of the top, which account for the stability of the levitation.

 

The Levitron consists of a base and a top. The base is a ring magnet with north oriented upwards. The top is a magnet with north oriented downwards. The two norths repel, thereby providing an upwards force on the top due to the magnetic field from the base.  A diagram can be found in Figure 1.

 

 

Figure 1: A simplified version of the Levitron.  The base is oriented such that it repels the top.  [1]

 

In the ideal case, the force on the top due to the magnetic field exactly balances the force due to gravity.  In order for these two vectors to cancel each other out, they need to be equal in magnitude and opposite in direction (compare Figure 2(a) and 2(b)).  The Levitron gives us two parameters to make sure the vectors come close to exactly canceling:  the weight of the top and the leveling of the base.  You can adjust the weight of the top by adding or removing small rubber, plastic, and copper rings, which come with the Levitron.  The legs of the base are adjustable, so that you can make sure it’s level on any surface.

 

 

Figure 2(a): Force diagram when Levitron is level, (b): when Levitron is at a tilt.

 

However, adjusting these two parameters alone are not enough to control stability. There will still be small deviations from the perfectly balanced state. Gyroscopic effects provide this stability. Once the top starts tilting, the forces on it due to both gravity and opposite poles attracting will cause there to be a torque on the top which tries to pull it back down to the base. The angular momentum of the top means that it resists reacting to this torque, and stays mostly upright.  See Figure 3 for a diagram of the torque.

 

 

Figure 3: The torque on the top due to the base magnet and gravity.

 

The other gyroscopic effect that leads to stability is that the top, when it moves off center, will realign to the local magnetic field and precess around it. While it is not intuitively obvious why this helps stability, mathematically, it is the key.  We can find the potential energy of the system by applying the adiabatic theorem to the system, a method we will not go into here. The result is that due to the top’s ability to reorient itself, there is a local potential minimum in the energy of the system. [2]  In other words, if the top wanders small amounts, it will be pushed back down the potential well.  A diagram of the field can be found in Figure 4, and an image of the top precessing can be found in Figure 5.

 

 

Figure 4: The curve in the magnetic field allows an equilibrium region to form. [3]

 

 

Figure 5: The top reorients itself based on the local magnetic field, and will precess around the local field. [1]

 

 

Miscellaneous

There are a few more things worth noting about the Levitron.  The first is that when the magnets heat up, the magnetic field decreases, and the weight on the top needs to be adjusted to account for the change.  Another thing is that when the top starts wobbling too much, the torque on the top will overcome the top’s ability to adjust, so it’s important to keep external disturbances to a minimum.  There are bounds on the rotation rate to ensure stability. When the angular velocity gets too high, the top can no longer reorient itself, and we lose the potential minimum. When it spins too slowly, the top can no longer counter the torque, and it is pulled back down to the plate. This low frequency is called ωcutoff.  In our experiments with the Levitron, we calculated that ωcutoff is around 19.4rps.

 

 

References

[1] Simon, Martin D. et al. 1997. “Spin stabilized magnetic levitation.” Am. J. Phys. 65: 286-292.

[2] Berry, M. V. 1996. “The Levitron: An Adiabatic Trap for Spins.” Proc. R. Soc. Lond. A 452: 1207-1220.

[3] Jones, T.B. 1997. “Simple Theory for the Levitron.” J. Appl. Phys. 82: 883-888.

[4] “The Physics of Levitron.” http://www.levitron.com/physics.html.

http://web.mit.edu/viz/levitron/Physics.html

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De: BARILOCHENSE6999 Enviado: 10/11/2024 16:32
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